# How do you solve the system -3x -8y = -9 and x+ 16y =3?

Jun 20, 2015

The solution is: $\left\{\begin{matrix}x = 3 \\ y = 0\end{matrix}\right.$

#### Explanation:

First you multiply the first equation by 2 and get:

$\left\{\begin{matrix}- 6 x - 16 y = - 18 \\ x + 16 y = 3\end{matrix}\right.$

Now you can add both equations to eliminate $y$.

$- 5 x = - 15$
$x = 3$

Now if you substitute $x$ in the 2nd equation you can calculate that: $y = 0$