How do you solve the system #4m+7n=0#, #-5m-3n=0#?

1 Answer
Mar 4, 2016

Answer:

#m=0#, #n=0#

Explanation:

To solve the system of simultaneous equations #4m+7n=0# and #−5m−3n=0#, we multiply the two with different numbers so as to make coefficient of one variable equal in both.

Hence multiplying first by #5# and second by #4#, we get

#20m+35n=0# and #−20m−12n=0#.

Now as coefficient of #m# are same but have opposite sign, add them and we get

#23n=0# i.e. #n=0#.

Putting this in say first equation, we get

#4*0+7n=0# or #7n=0# or #n=0#