How do you solve the system #4x=3y+31# and #y=2x+7# by substitution? Algebra Linear Inequalities and Absolute Value Linear Inequalities in Two Variables 1 Answer Ratnesh Bhosale May 24, 2018 #(-26,-45)# Explanation: #4x= 3y+31#-------(1) #y=2x+7#----------(2) Put (2) in (1), #4x= 3(2x+7)+31# #4x= 6x+21+31# #4x= 6x+52# #2x=-52# #x= -26# put in equation (2) #y=2(-26)+7# #y=-52+7# #y=-52+7# #y=-45# Answer link Related questions How do you graph linear inequalities in two variables? How many solutions does a linear inequality in two variables have? How do you know if you need to shade above or below the line? What is the difference between graphing #x=1# on a coordinate plane and on a number line? How do you graph #y \le 4x+3#? How do you graph #3x-4y \ge 12#? How do you graph #y+5 \le -4x+10#? How do you graph the linear inequality #-2x - 5y<10#? How do you graph the inequality #–3x – 4y<=12#? How do you graph the region #3x-4y>= -12#? See all questions in Linear Inequalities in Two Variables Impact of this question 2484 views around the world You can reuse this answer Creative Commons License