How do you solve the system #6x-2y=0# and #x-y=12# by substitution?

1 Answer
Don't Memorise
May 25, 2015

#6x-2y=0# .......equation #(1)#

#x-y=12#
# x = 12+y# ..........equation #(2)#

substituting equation #(2)# in equation #(1)#
#6(12+y)-2y=0#
#72+6y-2y=0#
#72= -4y#
#y = -18#

substituting the value of #y# in equation #(2)# to find #x#:

#x = 12+y = 12 -18 = -6#

the solution for the system of equations are
#color(blue)(x = -6 and y = -18#

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