How do you solve the system of equations 2x+y=2 and x-3y=-27?

Apr 4, 2018

Solution: $x = - 3 , y = 8$

Explanation:

2x+y=2; (1), x-3y=-27 ; (2) . Multiplying equation (2) by

$2$ we get # 2x-6y=-54 ; (3),subtracting equation (3)

from equation (1) we get, $7 y = 56 \therefore y = \frac{56}{7} = 8$ . Putting

$y = 8$ in equation (1) we get, $2 x + 8 = 2 \therefore 2 x = 2 - 8$ or

$2 x = - 6 \therefore x = - 3$

Solution: $x = - 3 , y = 8$ [Ans]