How do you solve the system of equations #5x - 3y = 1# and #9x - 4y = 6#?
Firstly, you have to multiply each equation so there is the same number of a letter in each equation. In this case it is easier to make both
#20x - 12y = 4
You can then take one equation away from the other. I will take the first away from the second:
You can then put this value of