How do you solve the system of equations $6x - 2y = 1$ and $2y - 10x = - 5$ ?

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Answer 1 · 2017-03-27T16:09:05

$x=1$ and $y=5/2$ or $2 1/2$

$:.6x-2y=1$ -------- $(1)$

$:.-10x+2y=-5$ ------ $(2)$

$:.(1)+(2)$ :

$:.-4x=-4$

multiply L.H.S. and R.H.S. by $-1$

$:.4x=4$

$:.x=1$

substitute $x=1$ in ----- $(1)$

$:.6(1)-2y=1$

$:.6-2y=1$

$-2y=1-6$

multiply L.H.S. and R.H.S. by $-1$

$:.2y=-1+6$

$:.2y=5$

$:.y=5/2$ or $2 1/2$

check:

substitute $x=1$ and $y=5/2$ in ----- $(1)$

$:.6(1)-2(5/2)=1$

$:.6-10/2=1$

$:.6-5=1$

$:.1=1$

How do you solve the system of equations 6x - 2y = 16x - 2y = 1 and 2y - 10x = - 52y - 10x = - 5?