Question

How do you solve the system of equations algebraically `2x+3y=3, 12x-15y=-4`?

Answer 1

`x=1/2, y=2/3`

Explanation:

Multiply the first eq. by 6 to get

12x +18y =18. Now subtract the second eq from this. x terms would get cancelled out.(This is called elimination)

33y= 22

`y= 2/3`

Now from 1st eq 2x= 3-3y

Or, `2x= 3-3( -2/3)`

`x=1/2`