# How do you solve the system of equations algebraically #2x+3y=3, 12x-15y=-4#?

##### 1 Answer

Feb 15, 2017

#### Answer:

#### Explanation:

Multiply the first eq. by 6 to get

12x +18y =18. Now subtract the second eq from this. x terms would get cancelled out.(This is called elimination)

33y= 22

Now from 1st eq 2x= 3-3y

Or,