# How do you solve the system of equations algebraically 2x+3y=3, 12x-15y=-4?

Feb 15, 2017

$x = \frac{1}{2} , y = \frac{2}{3}$

#### Explanation:

Multiply the first eq. by 6 to get

12x +18y =18. Now subtract the second eq from this. x terms would get cancelled out.(This is called elimination)

33y= 22

$y = \frac{2}{3}$

Now from 1st eq 2x= 3-3y

Or, $2 x = 3 - 3 \left(- \frac{2}{3}\right)$

$x = \frac{1}{2}$