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How do you solve the system of equations algebraically #4x-3y+2z=12, x+y-z=3, -2x-2y+2z=5#?

1 Answer

Feb 12, 2017

No solution

Explanation:

The system would have no solution because, Eq2 is #x+y=3+z# whereas Eq 3 is #x+y=-5/2 +z# .

As is evident, #x+y# can not be equal to 3+z and #-5/2#+z at the same time,

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