# How do you solve the system of equations algebraically 4x-3y+2z=12, x+y-z=3, -2x-2y+2z=5?

The system would have no solution because, Eq2 is $x + y = 3 + z$ whereas Eq 3 is $x + y = - \frac{5}{2} + z$ .
As is evident, $x + y$ can not be equal to 3+z and $- \frac{5}{2}$+z at the same time,