# How do you solve the system of equations algebraically #x=2y-8, 2x-y=-7#?

##### 1 Answer

Nov 14, 2017

#### Explanation:

#x=2y-8to(1)#

#2x-y=-7to(2)#

#"equation "(1)" gives x in terms of y so substitute into "(2)#

#rArr2(2y-8)-y=-7#

#rArr4y-16-y=-7#

#rArr3y=9rArry=3#

#"substitute this value into equation "(1)#

#x=(2xx3)-8=-2#

#"point of intersection "=(-2,3)#

graph{(y-1/2x-4)(y-2x-7)=0 [-10, 10, -5, 5]}