# How do you solve the system of equations algebraically #y=6-x, x=4.5+y#?

##### 1 Answer

Jan 19, 2017

#### Explanation:

We can substitute

#y=6-x" into " x=4.5+y#

#rArrx=4.5+(color(red)(6-x))larr" one variable"#

#rArrx=4.5+6-x#

#rArr2x=10.5# dividing by 2

#rArrx=5.25=21/4# Substitute this value into y = 6 - x

#x=21/4toy=6-21/4=3/4#

#rArr(21/4,3/4)" is the solution"# This could also have been solved by substituting

#x=4.5+y" into " y=6-x"# You may wish to attempt this yourself, as a check.