Question

How do you solve the system of equations algebraically `y=x+2z, z=-1-2x, x=y-14`?

Answer 1

Solution: `x=-4 ,y=10, z=7`

Explanation:

`y=x+2z (1) ; z= -1-2x (2) ; x=y-14 (3) :. y = x+14`

Putting `y = x+14` in equation (1) we get `cancelx+14 = cancelx+2z`

`:. 2z=14 or z=7` Putting `z=7` in equation (2 ) we get

`7= -1-2x or 2x= -1-7 or 2x =-8 or x= -4`

Putting `x=-4,z=7` in equation (1) we get

`y = -4 +2*7= -4+14=10 :. x=-4 ,y=10, z=7`

Solution: `x=-4 ,y=10, z=7` [Ans]