How do you solve the system of equations #-\frac { 3} { 4} x + y = - 1# and #- 3x + \frac { 1} { 2} y = 10#?

1 Answer
Mar 20, 2018

Answer:

#x=-4#, and #y=-1 3/16#

Explanation:

I'm going to use a method called substitution. First, add #3/4x# to both sides of the first equation. This leaves you with #y=3/4x-1#. Substitute this value of #y# into the second equation to get #-3x+1/2(3/4x-1)=10#. Simplify this equation to get #-3x+3/8x-1/2=10#. Combine like terms and simplify to get #-21/8x=21/2#. Divide on both sides by #-21# to get #1/8x=-1/2#. Multiply by 8 on both sides to get #x=-4#. Substitute this value of #x# into our equation of #y=3/4x-1# to get #y=-3/16-1=-1 3/16#.