How do you solve the system of equations #y= 6x + 5# and #y = 6x + 2#?

1 Answer
Aug 22, 2017

See a solution process below:

Explanation:

Both equations are in the slope-intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#y = color(red)(6)x + color(blue)(5)#

#y = color(red)(6)x + color(blue)(2)#

Both equations have the same slope: #color(red)(m = 6)#

Because both equations have the same slope they are, by definition, either the same line or parallel lines.

However, both equations have a different #y#-intercept.

The first equations #y#-intercept is: #color(blue)(b = 5)#

The second equations #y#-intercept is: #color(blue)(b = 2)#

If both equations represented the same line they would have each and every point in common. However, because they have different #y#-intercepts they must represent different but parallel lines.

Therefore, the is no solution to this system of equations. Or the solution is the null or empty set: #{O/}#