# How do you solve the system of linear equations 2x − 4y = 6 and 3x − y = 12?

Aug 25, 2016

$x = 4.2$
$y = 0.6$

#### Explanation:

Given -

$2 x - 4 y = 6$ ---------------(1)
$3 x - y = 12$----------------(2)

$- y = 12 - 3 x$
$y = - 12 + 3 x$

Substitute $y = - 12 + 3 x$ in equation (1)

$2 x - 4 \left(- 12 + 3 x\right) = 6$
$2 x + 48 - 12 x = 6$
$- 10 x + 48 = 6$
$- 10 x = 6 - 48 = - 42$
$x = \frac{- 42}{- 10} = 4.2$

Substitute $x = 6$ in equation (2)

$3 \left(4.2\right) - y = 12$
$12.6 - y = 12$
$- y = 12 - 12.6 = - 0.6$
$y = 0.6$