Question

How do you solve the system of linear equations `2x − 4y = 6` and `3x − y = 12`?

Answer 1

`x=4.2`
`y=0.6`

Explanation:

Given -

`2x-4y=6` ---------------(1)
`3x-y=12`----------------(2)

`-y=12-3x`
`y=-12+3x`

Substitute `y=-12+3x` in equation (1)

`2x-4(-12+3x)=6`
`2x+48-12x=6`
`-10x+48=6`
`-10x=6-48=-42`
`x=(-42)/(-10)=4.2`

Substitute `x=6` in equation (2)

`3(4.2)-y=12`
`12.6-y=12`
`-y=12-12.6=-0.6`
`y=0.6`