How do you solve the system using elimination $8x-3y=16$ and $8x+3y=-8$ ?

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Answer 1 · 2015-06-08T11:15:43

$8x-color(red)(3y)=16$ ...............equation $(1)$
$8x+color(red)(3y)=-8$ ...........equation $(2)$

Upon adding equations $(1)$ and $(2)$ we can eliminate $color(red)(3y$ and find $x$

$8x-cancelcolor(red)(3y)=16$
$8x+cancelcolor(red)(3y)=-8$

$16x=8$
$color(red)(x)=8/16 = color(red)(1/2$

Finding $y$ from equation $(2)$

$3y = - 8 - 8x$
$3y = - 8 - 8 . color(red)((1/2))$
$3y = - 8 - 4$
$3y = -12 , color(red)(y=-4$

The solutions for the system of equations are:
$color(red)( x = 1/2 , y=-4$

How do you solve the system using elimination 8x-3y=168x-3y=16 and 8x+3y=-88x+3y=-8?