# How do you solve the system using elimination 8x-3y=16 and 8x+3y=-8?

Jun 8, 2015

$8 x - \textcolor{red}{3 y} = 16$ ...............equation$\left(1\right)$
$8 x + \textcolor{red}{3 y} = - 8$...........equation $\left(2\right)$

Upon adding equations $\left(1\right)$ and $\left(2\right)$ we can eliminate color(red)(3y and find $x$

$8 x - \cancel{\textcolor{red}{3 y}} = 16$
$8 x + \cancel{\textcolor{red}{3 y}} = - 8$

$16 x = 8$
color(red)(x)=8/16 = color(red)(1/2

Finding $y$ from equation $\left(2\right)$

$3 y = - 8 - 8 x$
$3 y = - 8 - 8 . \textcolor{red}{\left(\frac{1}{2}\right)}$
$3 y = - 8 - 4$
3y = -12 , color(red)(y=-4

The solutions for the system of equations are:
color(red)( x = 1/2 , y=-4