To begin, plug in a equation for a variable that is already isolated. There are two variables that are already isolated, and those are xandz. You could choose either to work with, doesn't matter, but I'm going to use x
So, plug the equation for x into another equation that has that same variable in it. Which would be:
.196x=10.4y
To begin, plug x equation into .196x=10.4y
.196(175+15y)=10.4y
Distribute .196 throughout the set of parenthesis
34.3+2.94y=10.4y
Begin to isolate y by subtracting 34.3 on both sides of the equation
2.94y=−23.9
Isolate y by dividing 2.94 on both sides of the equation
y=−8.13
Now, we have solved for one of the variables. The next thing to do is plug y into another equation that contains y in it. An easy one to use would be x=175+15y because x is already isolated
So, plug y=−8.13 into x=175+15y
x=175+15(−8.13)
Distribute 15 throughout the set of parenthesis
x=175−121.95
Subtract
x=53.05
And now we have solved for y and x. The only variable left is z
To solve for z, you have to plug y=−8.13 into the equation
z=10(−8.13)
Multiply
z=−81.3
x=53.05
y=−8.13
z=−81.3
