How do you solve the system x + y - z = 2, x - y -z = 3, x - y - z = 4?

1 Answer
Nov 21, 2015

$\textcolor{red}{\text{The proposed question has a conflict, thus must be wrong}}$
Left hand side of Equation(2) is the same as the left hand side of Equation (3) but they are stated as being equal to different values!!!

Explanation:

Given
$x + y - z = 2. \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \left(1\right)$
$\textcolor{red}{x - y - z = \textcolor{b l u e}{3} \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots . \left(2\right)}$
$\textcolor{red}{x - y - z = \textcolor{g r e e n}{4} \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots . \left(3\right)}$