How do you solve the system #x + y - z = 2#, #x - y -z = 3#, #x - y - z = 4#?

1 Answer
Tony B
Nov 21, 2015

#color(red)("The proposed question has a conflict, thus must be wrong")#
Left hand side of Equation(2) is the same as the left hand side of Equation (3) but they are stated as being equal to different values!!!

Explanation:

Given
#x+y-z=2........................................(1)#
#color(red)(x-y-z=color(blue)(3)........................................(2))#
#color(red)(x-y-z=color(green)(4)........................................(3))#

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