Question

How do you solve the system `x^2-y-4=0` and `x^2+3y^2-4y-10=0`?

Answer 1

`y = -1, x=pmsqrt(3)`
`y = 2,x=pmsqrt(6)`

Explanation:

`{(x^2-y-4=0),(x^2+3y^2-4y-10=0):}`

Substracting the first from the second

`3(y^2-y-2)=0` with solutions

`y = -1, x=pmsqrt(3)`
`y = 2,x=pmsqrt(6)`