# How do you solve the system #x+y=1# and #2x-y=2#?

##### 1 Answer

Feb 28, 2016

#### Answer:

#x=1#

#y=0#

#### Explanation:

#x+y=1# --------------------- (1)

#2x-y=2# ------------------(2)

Solving the 1st equation for

#y=1-x#

Substitute

#2x-(1-x)=2#

Simplify and solve for

#2x-1+x=2#

#3x=2+1#

#x=3/3=1#

#x=1#

Substitute the value

#1+y=1#

#y=1-1#

#y=0#