How do you solve the system #x = y + 4# and #2x - 5y = 2# by substitution?

1 Answer
May 21, 2015

#x = y + 4# -----------(1)
#2x - 5y = 2#-----------(2)

Substituting #x# from the first equation into the second one gives us:

#2(y+4) - 5y = 2#

#2y+8 - 5y = 2#

# -3y + 8 = 2#

#-3y = 2-8#

#-3y = -6#

Dividing both sides by #-3# will give us:

#(cancel(-3)y)/cancel(-3) = (-6)/-3#

#color(green)(y = 2#

Substituting #y=2# in the first equation will give us :

#x = 2 + 4#

#color(green)(x = 6#

The solution to both these equations :#x = 6; y = 2#

Verify :

Substitute the values of #x and y# in both the equations to see if they are satisfied