How do you solve the system #x-y+z=3#, #2x+y+z=8#, and #3x+y-z=1#?
We are given three equations in three variables, which are
To solve them, what we need is to eliminate some vatiables to get the value of others.
It is apparent from (1) nd (3) that as signs of
Now subtracting (2) from (1), we get
Putting values of
Hence, solution is