# How do you solve the system #x-y+z=3#, #2x+y+z=8#, and #3x+y-z=1#?

##### 1 Answer

Solution is

#### Explanation:

We are given three equations in three variables, which are

**..........................................(1)**

**..........................................(2)**

and **..........................................(3)**

To solve them, what we need is to eliminate some vatiables to get the value of others.

It is apparent from **(1)** nd **(3)** that as signs of

Now subtracting **(2)** from **(1)**, we get

But as

Putting values of **(1)**, we get

Hence, solution is