How do you solve the system #y=5x-7 # and #-3x-2y=-12# by substitution? Algebra Linear Inequalities and Absolute Value Linear Inequalities in Two Variables 1 Answer Tessalsifi Jun 3, 2015 We know that #y=5x-7# so we are just going to replace the #y# in the other equation : #-3x-2y=-12# #-3x-2*(5x-7)=-12# #-3x-10x+14=-12# #-13x=-12-14# ( we substract #14# on each side ) #-13x=-26# #x=2# ( we divide by #-13# on each side ) Now that we have #x#, we can find #y# with the first equation : #y=5x-7# #y=5*2-7# #y=10-7# #y=3# Answer link Related questions How do you graph linear inequalities in two variables? How many solutions does a linear inequality in two variables have? How do you know if you need to shade above or below the line? What is the difference between graphing #x=1# on a coordinate plane and on a number line? How do you graph #y \le 4x+3#? How do you graph #3x-4y \ge 12#? How do you graph #y+5 \le -4x+10#? How do you graph the linear inequality #-2x - 5y<10#? How do you graph the inequality #–3x – 4y<=12#? How do you graph the region #3x-4y>= -12#? See all questions in Linear Inequalities in Two Variables Impact of this question 10520 views around the world You can reuse this answer Creative Commons License