# How do you solve the system  y= 6x - 11  and -2x - 3y = -7 by substitution?

##### 1 Answer
Jun 3, 2015

Given
$\text{[1] } y = 6 x - 11$
$\text{[2] } - 2 x - 3 y = - 7$

$\textcolor{w h i t e}{\text{XXXX}}$Using [1] substitute $\left(6 x - 11\right)$ for $y$ in [2]
$\text{[3] } - 2 x - 18 x + 33 = - 7$
$\textcolor{w h i t e}{\text{XXXX}}$Simplifying
$\text{[4] } 20 x = 40$
$\text{[5] } x = 2$
$\textcolor{w h i t e}{\text{XXXX}}$Using [5] substitute $4$ for $x$ in [1]
$\text{[6] } y = 12 - 11$
$\text{[7] } y = 1$

Solution is $\left(x , y\right) = \left(2 , 1\right)$