How do you solve the system # y= 6x - 11 # and #-2x - 3y = -7# by substitution? Algebra Linear Inequalities and Absolute Value Linear Inequalities in Two Variables 1 Answer Alan P. Jun 3, 2015 Given #"[1] "y = 6x-11# #"[2] "-2x-3y = -7# #color(white)("XXXX")#Using [1] substitute #(6x-11)# for #y# in [2] #"[3] " -2x - 18x+33 = -7# #color(white)("XXXX")#Simplifying #"[4] "20x = 40# #"[5] "x = 2# #color(white)("XXXX")#Using [5] substitute #4# for #x# in [1] #"[6] "y = 12 -11# #"[7] "y = 1# Solution is #(x,y) = (2,1)# Answer link Related questions How do you graph linear inequalities in two variables? How many solutions does a linear inequality in two variables have? How do you know if you need to shade above or below the line? What is the difference between graphing #x=1# on a coordinate plane and on a number line? How do you graph #y \le 4x+3#? How do you graph #3x-4y \ge 12#? How do you graph #y+5 \le -4x+10#? How do you graph the linear inequality #-2x - 5y<10#? How do you graph the inequality #–3x – 4y<=12#? How do you graph the region #3x-4y>= -12#? See all questions in Linear Inequalities in Two Variables Impact of this question 22296 views around the world You can reuse this answer Creative Commons License