How do you solve the system y = x +4y=x+4 and 2x + 3y = 222x+3y=22 by substitution?

1 Answer
May 21, 2015

You are given y=color(red)(x+4)y=x+4, so substitute this for the value of yy in
2x+3y = 222x+3y=22

2x + 3color(red)((x+4)) = 222x+3(x+4)=22

2x+3x+12 =222x+3x+12=22

5x= 105x=10

x=color(blue)(2)x=2

Now substitute this value for xx back into y=x+4y=x+4
y=color(blue)(2)+4y=2+4

y=6y=6