How do you solve the triangle given A=38*, b=10, a=8?

Jul 3, 2015

solve triangle : A = 38; b = 10 and a = 8

Explanation:

Find angles B and C, and sides c.

$\sin B = b \frac{\sin A}{a} = \frac{10 \left(0.62\right)}{8} = 0.77 \to B = 50.32$ deg

Angle $C = 180 - A - B = 180 - 38 - 50.32 = 91.68$ deg

Side $c = a \left(\sin \frac{C}{\sin} A\right) = 8 \left(\frac{099}{0.62}\right) = 12.77$