How do you solve the triangle given A=56, B=22, a=12.2? Trigonometry Triangles and Vectors The Law of Cosines 1 Answer sankarankalyanam Mar 25, 2018 # hat C = 102, b = 5.42, c = 14.39# #color(brown)("Perimeter of the triangle " = P = 32.01 " units"# #color(purple)("Area of the triangle " A_t ~~ 32.34 " sq units"# Explanation: Given : #hat A = 56, hat B = 22, a = 12.2# #hat C = 180 - (hat A + hat B) = 180 - 56 - 22 = 102# Applying Law of Sines, #12.2 / sin 56 = b / sin 22 = c / sin 102# #b = (12 * sin 22) / sin (56) ~~ 5.42# #c = (12.2 * sin 102) / sin 56 ~~ 14.39# #color(brown)("Perimeter of the triangle " = P = 12.2 + 5.42 + 14.39 = 32.01 " units"# #color(purple)("Area of the triangle " A_t = (1/2) a b sin C = (1/2) 12.2 * 5.42 * sin 102 ~~ 32.34 " sq units"# Answer link Related questions Does the law of cosines work for any triangle? How do you derive the law of cosines? How is the law of cosines related to the pythagorean theorem? How do you find the angle in the law of cosines? How do you use the law of cosines to find the area of a triangle? What is the law of cosines? When can the law of cosines be used? How do you find angles A, B, and C if in triangle ABC, #a=12#, #b=15#, and #c=20#? How do you find the measure of the smallest in an acute triangle whose side lengths are 4m, 7m, and 8m? Bong walks 100 m due North and then 150 m in a direction N 37 deg. E. How far is Bong from his... See all questions in The Law of Cosines Impact of this question 1813 views around the world You can reuse this answer Creative Commons License