Question

How do you solve the triangle using law of sines given a=8, b=9, c=10?

Answer 1

Given three sides of a triangle, angles can be found using cosine rule ans not the Rule of sines. Accordingly,cosA=`(b^2+c^2-a^2)/(2bc)`= `(81+100-64)/180= 17/180. A= arc cos(117/180)` = 49.45degrees. Like wise cosB= `83/160`. B= arc cos(83/160)=58.75 degrees. Then finally C= 180-49.45-58.75= 71.20