# How do you solve the triangles given a = 4, b = 3 and c = 6?

Jun 28, 2015

Solve the triangle

#### Explanation:

Use trig identity : c^2 = a^2 + b^2 - 2bc.cos C. Find angles A, B, and C.

36 = 16 + 9 - 24.cos C -> $\cos C = - \frac{11}{24} = - 0.46$ -> C = 117.28

16 = 9 + 36 - 36.cos A ->$\cos A = \frac{29}{36} = 0.81$ -> A = 36.34

Angle B = 180 - A - C = 180 - 117.28 - 36.34 = 26.38