Question

How do you solve this integral?

`inttan^2xdx`

Answer 1

`int tan^2x dx = tanx -x +C`

Explanation:

Use the identity:

`tan^2x = sec^2x -1`

and remember that:

`d/(dx) tanx = sec^2x`

so we have:

`int tan^2x dx = int (sec^2x -1) dx = int sec^2xdx - int dx = tanx -x +C`