# How do you solve this system of equations: 3x = 16+ 2y ; 5y = - 2x - 2?

Jul 11, 2018

$x = 4 , y = - 2$

#### Explanation:

From the second equation we get

$y = \frac{1}{5} \left(- 2 x - 2\right)$
plugging this (for $y$) in the first equation

$3 x = 16 + 2 \left(\frac{1}{5} \left(- 2 x - 2\right)\right)$
$3 x = 16 + \frac{2}{5} \left(- 2 x - 2\right)$
multiplying by $5$
$15 x = 80 - 4 x - 4$
so we get

$19 x = 76$
$x = 4$

and

$y = \frac{1}{5} \cdot \left(- 8 - 2\right) = - \frac{10}{5} = - 2$