How do you solve using gaussian elimination or gauss-jordan elimination, 2x₁+4x₂-6x₃= 10, 3x₁+3x₂-3x₃= 6?

1 Answer
Jan 6, 2018

P=({-1-p, 3+2p, p}, p in RR)

Explanation:

([2,4,-6,|,10],[3,3,-3,|,6])~~([6,12,-18,|,30],[6,6,-6,|,12])
R_1=R_1xx3
R_2=R_2xx2
R_2=R_2-R_1

([6,12,-18,|,30],[0,-6,12,|,-18])~~([1,2,-3,|,5],[0,1,-2,|,3])
R_1=R_1xx1/6
R_2=R_2xx-1/6
R_1=R_1-2xxR_2

([1,0,1,|,-1],[0,1,-2,|,3])

We have to set x_3 as parameter p:
x_1=-1-p
x_2=3+2p
x_3=pcolor(white)(QQQQQQQQQQQ)p in RR

P=({-1-p, 3+2p, p}, p in RR)