How do you solve using gaussian elimination or gauss-jordan elimination, $3x + y - 3z =3$ , $x + 3y - z = -7$ , $3x + 3y - z = -1$ ?

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Answer 1 · 2017-12-13T21:58:27

$x=3$ , $y=-3$ and $z=1$

From second equation, $z=x+3y+7$

I took value of $z$ into third one,

$3x+3y-(x+3y+7)=-1$

$2x-7=-1$

$2x=6$ , so $x=3$

After taking value of $z$ into first one,

$3x+y-3*(x+3y+7)=3$

$-8y-21=3$

$-8y=24$ , so $y=-3$

Thus $z=x+3y+7=3+3*(-3)+7=3-9+7=1$

How do you solve using gaussian elimination or gauss-jordan elimination, 3x + y - 3z =33x + y - 3z =3, x + 3y - z = -7x + 3y - z = -7, 3x + 3y - z = -13x + 3y - z = -1?