# How do you solve using gaussian elimination or gauss-jordan elimination, #X + 2Y- 2Z=1#, #2X + 3Y + Z=14#, #4Y + 5Z=27#?

##### 1 Answer

#### Answer:

#### Explanation:

We will use Gaussian and back-substitution.

We kick off with the starting augmented matrix (see the **NB** at bottom):

That was really quick, actually; and this is now in row echelon form.

We can see that:

We back substitute from:

So:

And:

**NB**

The augmented matrix will not necessarily be represented as it might be in your book as I can't find the functionality in the typesetter here. (So I've got a 3x3 and a column vector.)