# How do you solve using gaussian elimination or gauss-jordan elimination, x-3y=6 and x+6y=0?

$x = 4$ and $y = - \frac{2}{3}$
From $x + 6 y = 0$, $x = - 6 y$. Hence $x - 3 y = 6$ became $- 9 y = 6$. So,
$y = \frac{6}{- 9} = - \frac{2}{3}$ and $x = \left(- 6\right) \cdot \left(- \frac{2}{3}\right) = 4$