# How do you solve using the completing the square method 3x^2 + 11x - 4 = 0?

Aug 4, 2017

-4; $\frac{1}{3}$

#### Explanation:

$3 {x}^{2} + 11 x = 4$
Divide both sides by 3:
${x}^{2} + \frac{11 x}{3} = \frac{4}{3}$
${x}^{2} + \frac{11 x}{3} + \frac{121}{36} = \frac{4}{3} + \frac{121}{36}$
${\left(x + \frac{11}{6}\right)}^{2} = \frac{169}{36}$
$x + \frac{11}{6} = \pm \frac{13}{6}$
$x = - \frac{11}{6} \pm \frac{13}{6}$
$x 1 = - \frac{24}{6} = - 4$
$x 2 = \frac{2}{6} = \frac{1}{3}$