# How do you solve v^2+7v+12=0?

Nov 11, 2016

$v = - 4$ and $v = - 3$

#### Explanation:

${v}^{2} + 7 v + 12 = 0$

$\left(v + 4\right) \left(v + 3\right) = 0$

Then solve for each term of the quadratic:

1)

$\frac{\left(v + 4\right) \left(v + 3\right)}{v + 3} = \frac{0}{v + 3}$

$v + 4 = 0$

$v + 4 - 4 = 0 - 4$

$v = - 4$

2)

$\frac{\left(v + 4\right) \left(v + 3\right)}{v + 4} = \frac{0}{v + 4}$

$v + 3 = 0$

$v + 3 - 3 = 0 - 3$

$v = - 3$