How do you solve #w(4w+6)+2w=2(2w^2+7w-3)#?

1 Answer
Apr 26, 2018

Answer:

#w = 1#

Explanation:

#w(4w + 6) + 2w = 2(2w^2 + 7w - 3)#

Use the Distributive Property:
#w(4w + 6) + 2w = 2(2w^2 + 7w - 3)#
#4w^2 + 6w + 2w = 4w^2 + 14w - 6#

Combine Like Terms:
#4w^2 + 6w + 2w = 4w^2 + 14w - 6#
#4w^2 + 8w = 4w^2 + 14w - 6#

Use the Additive Inverse:
#4w^2 + 8w = 4w^2 + 14w - 6#
#8w = 14w - 6#
#-6x = -6#
#w = 1#

There's your answer!