How do you solve w(4w+6)+2w=2(2w^2+7w-3)?

1 Answer
Apr 26, 2018

w = 1

Explanation:

w(4w + 6) + 2w = 2(2w^2 + 7w - 3)

Use the Distributive Property:
w(4w + 6) + 2w = 2(2w^2 + 7w - 3)
4w^2 + 6w + 2w = 4w^2 + 14w - 6

Combine Like Terms:
4w^2 + 6w + 2w = 4w^2 + 14w - 6
4w^2 + 8w = 4w^2 + 14w - 6

Use the Additive Inverse:
4w^2 + 8w = 4w^2 + 14w - 6
8w = 14w - 6
-6x = -6
w = 1

There's your answer!