# How do you solve (x-1)(x+1)=3?

Jul 20, 2016

${x}^{2} + x - x - 1 = 3$

${x}^{2} - 1 - 3 = 0$

${x}^{2} - 4 = 0$

$\left(x + 2\right) \left(x - 2\right) = 0$

$x = \pm 2$

Hopefully this helps!