# How do you solve #|x - 2| = 1#?

##### 1 Answer

Dec 21, 2016

The solution is

#### Explanation:

To clear the absolute-value bars, I must split the equation into its two possible two cases, one case for each sign:

#(x-2) = 1" "# or#" "-(x-2) = 1#

#x = 1+2" "# or#" " -x+2 = 1#

#x = 3" " " "# or#" " " " x=2-1=1#

Then the solutions are