How do you solve #|x - 2| = 1#?

1 Answer

Answer:

The solution is #x = 3# or #x=1#

Explanation:

To clear the absolute-value bars, I must split the equation into its two possible two cases, one case for each sign:

#(x-2) = 1" "# or #" "-(x-2) = 1#

#x = 1+2" "# or #" " -x+2 = 1#

#x = 3" " " "# or #" " " " x=2-1=1#

Then the solutions are #x = 3# or #x= 1#