How do you solve x^2 - 12x + 36 = 49?

Apr 23, 2016

$x = - 1$
$x = 13$

Explanation:

Given -

${x}^{2} - 12 x + 36 = 49$
${x}^{2} - 12 x + 36 - 49 = 0$
${x}^{2} - 12 x - 13 = 0$
${x}^{2} + x - 13 x - 13 = 0$
$x \left(x + 1\right) - 13 \left(x + 1\right) = 0$
$\left(x + 1\right) \left(x - 13\right) = 0$
$x = - 1$
$x = 13$