How do you solve #x^2-15x+54=0#? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Suren Abreu Jan 16, 2017 #x=6# or #x=9# Explanation: #x^2-15x+54=0# Factorise. #x^2-9x-6x+54=0# #x(x-9)-6(x-9)=0# #(x-6)(x-9)=0# #x-6=0# or #x-9=0# #x=6# or #x=9# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 16738 views around the world You can reuse this answer Creative Commons License