How do you solve #x^2 - 16 = 0# by factoring?

1 Answer
Sep 29, 2015

Answer:

The solutions are
#color(blue)(x=-4,x=4#

Explanation:

As per property
#color(blue)(a^2-b^2)=(a+b)(a-b)#

Expressing the given equation in the same manner:

#x^2-16=color(blue)(x^2-4^2#

#x^2-4^2 = color(blue)((x+4)(x-4)#

Now we equate the factors to zero to obtain the solutions

#x+4 =0, color(blue)(x=-4#
#x-4 =0, color(blue)(x=4#