Question

How do you solve `x^2-18x=-32`?

Answer 1

Start by turning it into a quadratic equation in standard form...

Explanation:

...by adding 32 to both sides. You then have:

`x^2 - 18x + 32 = 0`

And then you might be able to factor it directly. By noting that
`-2 * -16 = 32` and `-2 - 16 = -18`

`(x - 2)(x-16) = 0`

...so then you can see that if x = 2 or x = 16, then the equation is true.