# How do you solve x^2-18x=-32?

Aug 29, 2017

Start by turning it into a quadratic equation in standard form...

#### Explanation:

...by adding 32 to both sides. You then have:

${x}^{2} - 18 x + 32 = 0$

And then you might be able to factor it directly. By noting that
$- 2 \cdot - 16 = 32$ and $- 2 - 16 = - 18$

$\left(x - 2\right) \left(x - 16\right) = 0$

...so then you can see that if x = 2 or x = 16, then the equation is true.