How do you solve x^2-18x+81=0 by factoring? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Konstantinos Michailidis Oct 1, 2015 It is x^2-18x+81=0=>x^2-2*9*x+9^2=0=>(x-9)^2=0=>x=9 We used the identity (a-b)^2=a^2-2ab+b^2 Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial 10x^3-5x^2=0? Can you apply the zero product property in the problem (x+6)+(3x-1)=0? How do you solve the polynomial 24x^2-4x=0? How do you use the zero product property to solve (x-5)(2x+7)(3x-4)=0? How do you factor and solve b^2-\frac{5}{3b}=0? Why does the zero product property work? How do you solve (x - 12)(5x - 13) = 0? How do you solve (2u+7)(3u-1)=0? See all questions in Zero Product Principle Impact of this question 5088 views around the world You can reuse this answer Creative Commons License