# How do you solve x^2-2x-10=5?

Jun 30, 2017

-3 and 5

#### Explanation:

$y = {x}^{2} - 2 x - 15 = 0$
Find 2 real roots, with opposite signs (ac < 0), knowing sum (-b = 2) and product (c = - 15).
They are: -3 and 5. (because sum = -b = 2 and product - 15)

NOTE. When a = 1 it isn't necessary to use the lengthy solving by grouping and solving the 2 binomials.