Question

How do you solve `x^2-2x-10=5`?

Answer 1

-3 and 5

Explanation:

`y = x^2 - 2x - 15 = 0`
Find 2 real roots, with opposite signs (ac < 0), knowing sum (-b = 2) and product (c = - 15).
They are: -3 and 5. (because sum = -b = 2 and product - 15)

NOTE. When a = 1 it isn't necessary to use the lengthy solving by grouping and solving the 2 binomials.