How do you solve #x^2+3x+1=0# using the quadratic formula?

1 Answer
Apr 7, 2016

Answer:

Solution is given by irrational numbers #(-3+sqrt5)/2# and #(-3-sqrt5)/2#.

Explanation:

The solution of a quadratic equation #ax^2+bx+c=0#, using quadratic formula is given by #(-b+-sqrt(b^2-4ac))/(2a)#

Hence the solution of #x^2+3x+1=0# is given by

#x=(-3+-sqrt(3^2-4*1*1))/(2*1)# or

#x=(-3+-sqrt(9-4))/2=(-3+-sqrt5)/2#

Hence solution is given by irrational numbers #(-3+sqrt5)/2# and #(-3-sqrt5)/2#.