# How do you solve x^2 + 3x -2=0?

Dec 6, 2016

You can use the quadratic formula.

#### Explanation:

${x}^{2} + 3 x - 2 = 0$ is a quadratic equation in the form $a {x}^{2} + b x - 2 = 0$ where $a = 1$, $b = 3$, and $c = - 2$.

To solve this equation we can use the quadratic formula.

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

Plug the given values into the formula.

$x = \frac{- 3 \pm \sqrt{{3}^{2} - 4 \cdot 1 \cdot - 2}}{2 \cdot 1}$

$x = \frac{- 3 \pm \sqrt{9 + 8}}{2}$

$x = \frac{- 3 \pm \sqrt{17}}{2}$

$x = \frac{- 3 + \sqrt{17}}{2} , \frac{- 3 - \sqrt{17}}{2}$