# How do you solve x^2-4x-2=0?

$x = 2 \pm \sqrt{6}$
Complete the square for $x$:
${x}^{2} - 4 x - 2 = {\left(x - 2\right)}^{2} - 6 = 0$
Then rearrange to make $x$ the subject:
$x - 2 = \pm \sqrt{6} \implies x = 2 \pm \sqrt{6}$