How do you solve  x^2+4x-5=0 ?

Mar 7, 2018

$x = - 5 \mathmr{and} + 1$

Explanation:

First, factor this equation. Then, determine what two values add to equal to the middle term $\left(+ 4\right)$ and multiply to the last term $\left(- 5\right)$,

$+ 5 \mathmr{and} - 1$

Plug it in the equation:

$\left(x + 5\right) \left(x - 1\right)$

and set equal to zero

$\left(x + 5\right) \left(x - 1\right) = 0$

$x + 5 = 0 \implies x = - 5$

$x - 1 = 0 \implies x = + 1$